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| Both sides previous revision Previous revision Next revision | Previous revision | ||
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syntax:arrays [2018/08/22 06:49] ebersphi |
syntax:arrays [2019/11/03 16:45] (current) ersen fix a typo |
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| </code> | </code> | ||
| - | ''a[0]'' is assigned to the result of ''2+4''. ''a[1]'' gets the result of ''2+2''. The last index in the first assignment is the result of ''a[2]'', which has already been assigned as ''4'', and its value is also given ''a[2]''. | + | ''a[0]'' is assigned to the result of ''2+4''. ''a[2]'' gets the result of ''2+2''. The last index in the first assignment is the result of ''a[2]'', which has already been assigned as ''4'', and its value is also given ''a[2]''. |
| This shows that even though any existing arrays named ''a'' in the current scope have already been unset by using ''='' instead of ''+='' to the compound assignment, arithmetic variables within keys can self-reference any elements already assigned within the same compound-assignment. With integer arrays this also applies to expressions to the right of the ''=''. (See [[#evaluation_order | evaluation order]], the right side of an arithmetic assignment is typically evaluated first in Bash.) | This shows that even though any existing arrays named ''a'' in the current scope have already been unset by using ''='' instead of ''+='' to the compound assignment, arithmetic variables within keys can self-reference any elements already assigned within the same compound-assignment. With integer arrays this also applies to expressions to the right of the ''=''. (See [[#evaluation_order | evaluation order]], the right side of an arithmetic assignment is typically evaluated first in Bash.) | ||
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| $ touch xy=foo | $ touch xy=foo | ||
| + | + touch xy=foo | ||
| $ declare x[y]=* | $ declare x[y]=* | ||
| + declare 'x[y]=*' | + declare 'x[y]=*' | ||